touchesEnded中区分触摸类型

公司项目中需要为一个view添加手势，短按则消失，长按就保存到相册，为了在

touchesEnded中区分长按和短按开始了google和百度，百度中有人说可以通过以下方式来实现：

- (void)touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event{    UITouch *aTouch = [touches anyObject];    for(int i = 0; i < [aTouch.gestureRecognizers count] ;i ++){        UIGestureRecognizer *gesture = [aTouch.gestureRecognizers objectAtIndex:i];        if([gesture isKindOfClass:[UILongPressGestureRecognizer class]]){            //do what you want to do...        }    }}

经过验证发现aTouch.gestureRecognizers.count为0，根本无法判断是否长按，万般无奈下只好为view添加了UILongPressGestureRecognizer和UITapGestureRecognizer手势，功能倒是实现，可心里还是不舒服，觉得ios不应该犯如此低级错误，居然在touchesEnded里无法区分长按短按，心塞啊~

好吧，为了消除我心中的郁闷，继续研究，打印长按和短按的touch信息

短按：

 phase: Ended tap count: 1 window: ; layer = > view: > location in window: {198.66667175292969, 332} previous location in window: {197, 332.66665649414062} location in view: {122.000005086263, 115.33333333333337} previous location in view: {120.33333333333331, 115.999989827474}

长按：

 phase: Ended tap count: 0 window: ; layer = > view: > location in window: {184.66667175292969, 454.66665649414062} previous location in window: {188.33332824707031, 455.33334350585938} location in view: {108.000005086263, 237.999989827474} previous location in view: {111.66666158040363, 238.66667683919275}

突然发现tap count是不同的，再查苹果的文档，果然如此，于是就有了以下轻松愉快的代码：

-(void) touchesEnded:(NSSet *)touches withEvent:(UIEvent *)event{    UITouch *aTouch = [touches anyObject];    NSInteger tapCount = aTouch.tapCount;    if (1 == tapCount) { //短按        [self removeFromSuperview];    }    else if (0 == tapCount) { //长按        UIImage *p_w_picpath = [self captureView];        UIImageWriteToSavedPhotosAlbum(p_w_picpath, self, @selector(p_w_picpath:didFinishSavingWithError:contextInfo:), nil);    }}

搞定，打完收工。。。