二叉排序树创建(递归)
发表于:2024-11-26 作者:热门IT资讯网编辑
编辑最后更新 2024年11月26日,#include#include/*递归前中后遍历*/typedef struct node{ int data; struct node*left; struct node*right;}BT
#include#include /*递归前中后遍历*/typedef struct node{ int data; struct node*left; struct node*right;}BTnode;BTnode* CreateTree(BTnode* root,int x){ if(!root) //如果root结点为空,创建叶子结点 { root = (BTnode*)malloc(sizeof(BTnode)); root->data = x; root->left=root->right=NULL; }else { if(root->data>x) root->left = CreateTree(root->left,x); //递归调用左 else if(root->data right = CreateTree(root->right,x);//递归调用右 } return root;}void Forder(BTnode*root){ if(root) { printf("%d",root->data); printf("\n"); Forder(root->left); Forder(root->right); }}void Inorder(BTnode*root){ if(root) { Inorder(root->left); printf("%3d",root->data); printf("\n"); Inorder(root->right); }}void Porder(BTnode*root){ if(root) { Porder(root->left); Porder(root->right); printf("%6d",root->data); printf("\n"); }}int main(void){ BTnode * head = NULL; int x; int n; int i; printf("请输入n="); scanf("%d",&n); printf("请输入二叉树的结点data\n"); for(i=0;i